11x^2-33x+22=0

Solution for 11x^2-33x+22=0 equation:

11x^2-33x+22=0

a = 11; b = -33; c = +22;
Δ = b2-4ac
Δ = -332-4·11·22
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-11}{2*11}=\frac{22}{22}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+11}{2*11}=\frac{44}{22}
=2
$